2y^2-12y+32=0

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Solution for 2y^2-12y+32=0 equation: 



2y^2-12y+32=0

a = 2; b = -12; c = +32;
Δ = b2-4ac
Δ = -122-4·2·32
Δ = -112
Delta is less than zero, so there is no solution for the equation

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